Entropy Calculator

Use this entropy calculator to estimate entropy change from thermodynamic data or simple ideal-gas expansion scenarios.

--

Run the calculator.

Quick Answer: Common entropy relations are ΔS = (ΔH - ΔG) / T, ΔS = Qrev / T, and for isothermal ideal-gas expansion ΔS = nR ln(V2 / V1).

What This Entropy Calculator Helps You Do

This page covers the three entropy calculations most people actually need: recover ΔS from Gibbs and enthalpy data, compute ΔS from reversible heat transfer, or estimate the entropy change of an ideal-gas volume change. That keeps the calculator useful across chemistry and thermodynamics coursework.

The result text calls out the sign of ΔS directly so you can move from the number to the physical interpretation without another step.

How to Calculate Entropy Calculator

  1. Choose the entropy workflow: Use Gibbs mode for thermodynamic reaction data, heat-transfer mode for reversible heating or cooling, or ideal-gas mode for isothermal expansion.
  2. Enter the required state variables: The calculator uses Kelvin internally and converts energy units where needed.
  3. Compute the entropy change: Each mode applies the matching thermodynamic equation and reports the sign and magnitude of ΔS.
  4. Interpret the sign: Positive entropy change indicates increasing disorder or accessible microstates, while negative entropy change indicates increasing order.

Entropy Calculator Formula

ΔS = (ΔH - ΔG) / T; ΔS = Qrev / T; ΔS = nR ln(V2 / V1)
Variable Meaning Unit
ΔS Entropy change J/mol·K or J/K
ΔH Enthalpy change kJ/mol
ΔG Gibbs free energy change kJ/mol
Qrev Reversible heat transfer J or kJ
T Absolute temperature K

Use the worked examples below to check how the formula behaves with real values. If the result looks unexpected, verify the unit assumptions and the meaning of each variable before interpreting the answer.

Worked Examples

Gibbs mode - Reaction thermodynamics
  • ΔH: -92.0 kJ/mol
  • ΔG: -32.0 kJ/mol
  • T: 298 K

Result: ΔS is about -201.3 J/mol·K.

The reaction can still be spontaneous even with negative entropy if enthalpy is favorable enough.

Heat mode - Reversible heating
  • Qrev: 2.50 kJ
  • T: 350 K

Result: ΔS is 7.14 J/K.

Adding reversible heat at constant temperature raises entropy.

Ideal gas mode - Volume doubling
  • n: 1.0 mol
  • V1: 1.0 L
  • V2: 2.0 L
  • T: 300 K

Result: ΔS is 5.76 J/mol·K.

Doubling the accessible volume increases the number of possible molecular arrangements.

Cooling example - Heat removed reversibly
  • Qrev: -1.80 kJ
  • T: 273 K

Result: ΔS is -6.59 J/K.

Removing heat reversibly lowers entropy.

How to Interpret Your Results

Range Meaning Action
Negative ΔS Entropy decreases. Expect greater order, less accessible volume, or heat leaving the system.
ΔS near zero Little entropy change. Check whether the process is close to balanced or whether inputs were rounded.
Positive ΔS Entropy increases. Expect more disorder, more dispersal, or more accessible microstates.

Frequently Asked Questions

One common route is ΔS = (ΔH - ΔG) / T when enthalpy, Gibbs free energy, and temperature are known.

Entropy rises because molecules have more accessible positions and arrangements.

Thermodynamic equations use absolute temperature, so Kelvin is required for a physically meaningful result.

Yes. Processes that increase order or remove reversible heat from a system can have negative entropy change.
Note: These equations describe standard textbook scenarios. Complex real systems can require temperature-dependent heat capacities or more detailed state models.

References

Last reviewed: March 2026